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Question
Balance the following equation:
\[\ce{KHCO3->K2CO3 + H2O + CO2}\]
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Solution
\[\ce{KHCO3->K2CO3 + H2O + CO2}\]
Multiply KHCO3 by 2 on left side
\[\ce{2KHCO3->K2CO3 + H2O + CO2}\]
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