Advertisements
Advertisements
Question
Bajinder runs ten times around a square track and covers 4 km. Find the length of the track.
Advertisements
Solution
Let a be the side of the square track.
Perimeter of the square track = 4a
Bajinder runs ten times around the square track and covers 4 km.
i.e., 10 × 4a = 4 km
⇒ 40a = 4 × 1000 m ...[∵ 1 km = 1000 m]
⇒ a = `(4 xx 1000)/40` m = 100 m
∴ Length of the track = 4a
= 4 × 100 m
= 400 m
APPEARS IN
RELATED QUESTIONS
The perimeter of a square is 36 cm; find its area
The table given below contains some measures of the square. Find the unknown values.
| Side | Perimeter | Area |
| 6 cm | ? | ? |
Draw a square B whose side is twice of the square A. Calculate the perimeter of the squares A and B
Measure the side of the red square on the dotted sheet. Draw here as many rectangles as possible using 12 such squares.
How many rectangles could you make?
1 sq cm = ______ cm × 1 cm.
In an exhibition hall, there are 24 display boards each of length 1 m 50 cm and breadth 1 m. There is a 100 m long aluminium strip, which is used to frame these boards. How many square metres of cloth is required to cover all the display boards? What will be the length in m of the cloth used, if its breadth is 120 cm?
Find the side of the square whose perimeter is 20 m.
If each side of a rhombus is doubled, how much will its area increase?
In the following figure, perimeter of (ii) is 18 units.
 |
| (ii) |
Three squares are attached to each other as shown in the following figure. Each square is attached at the mid-point of the side of the square to its right. Find the perimeter of the complete figure.
