Advertisements
Advertisements
प्रश्न
Bajinder runs ten times around a square track and covers 4 km. Find the length of the track.
Advertisements
उत्तर
Let a be the side of the square track.
Perimeter of the square track = 4a
Bajinder runs ten times around the square track and covers 4 km.
i.e., 10 × 4a = 4 km
⇒ 40a = 4 × 1000 m ...[∵ 1 km = 1000 m]
⇒ a = `(4 xx 1000)/40` m = 100 m
∴ Length of the track = 4a
= 4 × 100 m
= 400 m
APPEARS IN
संबंधित प्रश्न
The side of a square is 10 cm. If its side is tripled, then by how many times will its perimeter increase?
Your garden is in the shape of a square of side 5 m. Each side is to be fenced with 2 rows of wire. Find how much amount is needed to fence the garden at ₹ 10 per metre
A side of a square-shaped sandbox in Gandhi Park measures 30 cm. Determine the perimeter of the sandbox
1 sq m = 1 m × ______ m = 100 cm × ______ cm.
In the following figure, each square is of unit length
- What is the perimeter of the rectangle ABCD?
- What is the area of the rectangle ABCD?
- Divide this rectangle into ten parts of equal area by shading squares. (Two parts of equal area are shown here)
- Find the perimeter of each part which you have divided. Are they all equal?
The perimeter of a square garden is 48 m. A small flower bed covers 18 sq m area inside this garden. What is the area of the garden that is not covered by the flower bed? What fractional part of the garden is covered by flower bed? Find the ratio of the area covered by the flower bed and the remaining area.
Sweety runs around a square park of side 75 m. Bulbul runs around a rectangular garden with a length of 60 m and a breadth of 45 m. Who covers less distance?
In the following figure, perimeter of (ii) is 18 units.
 |
| (ii) |
Two figures can have the same area but different perimeters.
Three squares are attached to each other as shown in the following figure. Each square is attached at the mid-point of the side of the square to its right. Find the perimeter of the complete figure.
