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At what height above the earth's surface would the value of acceleration due to gravity be half of what it is on the surface? Take the radius of earth to be R. - Physics

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Question

At what height above the earth's surface would the value of acceleration due to gravity be half of what it is on the surface? Take the radius of earth to be R.

Short/Brief Note
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Solution

As we know

`g= GxxM/R^2`

So let at height H the value of g is half that of the earth earth surface

then g at R + H would be equal to

`g'= GxxM/(R+H)^2`
Now g'/g=1/2
1/2= R2/ (R+H)2
(R+H)2=2R2
R+H = √2 R
H = (√2-1) R

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Chapter 3: Laws of Motion - Exercise 2 [Page 126]

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Frank Physics [English] Class 9 ICSE
Chapter 3 Laws of Motion
Exercise 2 | Q 34 | Page 126
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