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Question
At 33K, N2O4 is fifty percent dissociated. Calculate the standard free energy change at this temperature and at one atmosphere.
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Solution
Given T = 33 K
\[\ce{N2O4 ⇌ 2NO2}\]
Initial concentration: 100% and 0
Concentration dissociated: 50%
Concentration remaining at equilibrium: 50% and 100%
Keq = `100/50` = 2
∆G0 = −2.303 RT log Keq
∆G0= −2.303 × 8.314 × 33 × log 2
∆G0 = −190.18 J mol−1
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