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At 33K, N2O4 is fifty percent dissociated. Calculate the standard free energy change at this temperature and at one atmosphere.

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प्रश्न

At 33K, N2O4 is fifty percent dissociated. Calculate the standard free energy change at this temperature and at one atmosphere.

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उत्तर

Given T = 33 K

\[\ce{N2O4 ⇌ 2NO2}\]

Initial concentration: 100% and 0

Concentration dissociated: 50%

Concentration remaining at equilibrium: 50% and 100%

Keq = `100/50` = 2

∆G0 = −2.303 RT log Keq

∆G0= −2.303 × 8.314 × 33 × log 2

∆G0 = −190.18 J mol−1

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Gibbs Free Energy (G)
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पाठ 7: Thermodynamics - Evaluation [पृष्ठ २२७]

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सामाचीर कलवी Chemistry - Volume 1 and 2 [English] Class 11 TN Board
पाठ 7 Thermodynamics
Evaluation | Q II. 42. | पृष्ठ २२७
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