Question

Assuming the acceleration remains constant, how long will Mahendra take to move 1 cm towards Virat?

Answer 1

Here, u = 0

∴ `s = ut + 1/2 at^2 = 0 + 1/2 at^2`

∴ `t = sqrt((2s)/a) = sqrt((2 xx 1 xx 10^-2  "m")/(5.34 xx 10^-9  "m/s"^2))`

= `sqrt(0.3745 xx 10^7 s^2)`

= `sqrt(3.745 xx 10^6)` s

1935 s = 32 minutes 15 seconds.