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प्रश्न
Assuming the acceleration remains constant, how long will Mahendra take to move 1 cm towards Virat?
संख्यात्मक
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उत्तर
Here, u = 0
∴ `s = ut + 1/2 at^2 = 0 + 1/2 at^2`
∴ `t = sqrt((2s)/a) = sqrt((2 xx 1 xx 10^-2 "m")/(5.34 xx 10^-9 "m/s"^2))`
= `sqrt(0.3745 xx 10^7 s^2)`
= `sqrt(3.745 xx 10^6)` s
1935 s = 32 minutes 15 seconds.
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