English

Assertion (A): The radius of a hemisphere increases from r cm to 2r cm. The ratio between the surface areas of the original hemisphere and the resulting hemisphere is 1 : 4.

Advertisements
Advertisements

Question

Assertion (A): The radius of a hemisphere increases from r cm to 2r cm. The ratio between the surface areas of the original hemisphere and the resulting hemisphere is 1 : 4.

Reason (R): Surface area in the first case = πr2 + 2πr2 and surface area in the second case = π(2r)2 + 2π(2r)2.

Options

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

MCQ
Assertion and Reasoning
Advertisements

Solution

Both A and R are true and R is the correct reason for A.

Explanation:

The total surface area of a hemisphere is given by πr2 + 2πr2 = 3πr2 . For radius r, the area is 3πr2, and for radius 2r, the area is 3π(2r)2 = 12πr2. The ratio of the original area to the resulting area is \[\frac{3\pi r^2}{12\pi r^2} = \frac{1}{4}\] (or 1 : 4). Both Assertion A and Reason R are true, with R correctly outlining the surface area formulas.

shaalaa.com
  Is there an error in this question or solution?
Chapter 20: Solids [Surface Area and Volume of 3-D Solids] - TEST YOURSELF [Page 304]

APPEARS IN

Selina Concise Mathematics [English] Class 9 ICSE
Chapter 20 Solids [Surface Area and Volume of 3-D Solids]
TEST YOURSELF | Q 1. (g) | Page 304
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×