मराठी

Assertion (A): The radius of a hemisphere increases from r cm to 2r cm. The ratio between the surface areas of the original hemisphere and the resulting hemisphere is 1 : 4.

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प्रश्न

Assertion (A): The radius of a hemisphere increases from r cm to 2r cm. The ratio between the surface areas of the original hemisphere and the resulting hemisphere is 1 : 4.

Reason (R): Surface area in the first case = πr2 + 2πr2 and surface area in the second case = π(2r)2 + 2π(2r)2.

पर्याय

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

MCQ
विधान आणि तर्क
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उत्तर

Both A and R are true and R is the correct reason for A.

Explanation:

The total surface area of a hemisphere is given by πr2 + 2πr2 = 3πr2 . For radius r, the area is 3πr2, and for radius 2r, the area is 3π(2r)2 = 12πr2. The ratio of the original area to the resulting area is \[\frac{3\pi r^2}{12\pi r^2} = \frac{1}{4}\] (or 1 : 4). Both Assertion A and Reason R are true, with R correctly outlining the surface area formulas.

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 20: Solids [Surface Area and Volume of 3-D Solids] - TEST YOURSELF [पृष्ठ ३०४]

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सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 20 Solids [Surface Area and Volume of 3-D Solids]
TEST YOURSELF | Q 1. (g) | पृष्ठ ३०४
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