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Assertion (A): ABCD is a square. E is mid-point of side AB and F is mid-point of side DC. If DA = 16 cm, the area of triangle COF is 32 cm2. Reason (R): EF is ⊥ to DC and OF = 1/2 EF = 1/2 DA = 8 cm.

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Question

Assertion (A): ABCD is a square. E is mid-point of side AB and F is mid-point of side DC. If DA = 16 cm, the area of triangle COF is 32 cm2.

Reason (R): EF is ⊥ to DC and OF = `1/2` EF = `1/2` DA = 8 cm. Area of COF = `1/2` × CF × OF.

Options

  • A is true, R is false.

  • A is false, R is true.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true and R is the incorrect reason for A.

MCQ
Assertion and Reasoning
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Solution

Both A and R are true and R is the correct reason for A.

Explanation:

  • Reason (R): In square ABCD, EF connects the mid-points of opposite sides AB and DC, making EF perpendicular to DC and equal in length to side DA (EF = DA = 16 cm). Because the diagonal AC and line segment EF bisect each other at point O, the length of OF is half of EF: OF = `1/2` × 16 = 8 cm. Since F is the mid-point of DC, CF = `1/2 xx "DC" = 1/2 xx 16` = 8 cm. The area of right-angled triangle COF is given by `1/2` × CF × OF = `1/2` × 8 × 8 = 32 cm2. Thus, Reason (R) is true.
  • Assertion (A): The calculations in Reason (R) directly prove that the area of triangle COF is 32 cm2, meaning Assertion (A) is also true and is correctly explained by Reason (R).
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Chapter 15: Area Theorems [Proof and Use] - TEST YOURSELF [Page 224]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 15 Area Theorems [Proof and Use]
TEST YOURSELF | Q 1. (h) | Page 224
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