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Question
Answer the following.
What is the stress in a wire which is 50m long and 0.01 cm2 in cross-section, if the wire bears a load of 100 kg?
Sum
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Solution
Given: M = 100 kg, L = 50 m, A = 0.01 × 10-4 m
To find: Stress
Formula: Stress = `"F"/"A" = "Mg"/"A"`
`"Stress" = (100 xx 9.8)/(0.01 xx 10^-4) = 9.8 xx 10^8 "N"//"m"^2`
The stress in the wire is 9.8 × 108 N/m2.
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Chapter 6: Mechanical Properties of Solids - Exercises [Page 113]
