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Question
Answer the following question.
What are the dimensions of the quantity `lsqrt(l//g)`, l being the length, and g the acceleration due to gravity?
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Solution
∴ [g] = `"m"/"s"^2 = ["L"]/["T"^2]`
[k] = `[l sqrt("l"/"g")]`
[k] = [L] `[sqrt("L"/"g")]`
= [L] `[sqrt("L"/[["L"/"T"^2]])]`
= [L] `[sqrt(("LT"^2)/"L")]`
= [L] `[sqrt("T"^2)]`
= [L] [T]
= [L1 T1]
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