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Question
Answer the following:
If log3 [log2 (log3x)] = 1, show that x = 6561
Sum
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Solution
log3 [log2 (log3x)] = 1
∴ log2 (log3x) = 31 = 3
∴ log3x = 23 = 8
∴ x = 38 = 6561.
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Chapter 6: Functions - Miscellaneous Exercise 6.2 [Page 131]
