Question

Answer the following:

If log₃ [log₂ (log₃x)] = 1, show that x = 6561

Answer 1

log₃ [log₂ (log₃x)] = 1

∴ log₂ (log₃x) = 3¹ = 3

∴ log₃x = 2³ = 8

∴ x = 3⁸ = 6561.