Question

An unbiased cubic die is thrown .Find the probability of getting
(iii) a number divisible by 2

Answer 1

When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6. So,
total number of possible outcomes =6 

The event is getting a number divisible by 2 and numbers divisible by 2 are 2,4,6. So, the number of favourable outcomes to the event getting a number divisible by 2 = 3 

Therefore , P(getting a number divisible by 2) = `"Favourable outcomes "/"Total number of outcomes "` = `3/6` = `1/2`