Question

An unbiased cubic die is thrown .Find the probability of getting 
(ii) a number greater than 2

Answer 1

When a die is tossed once, the possible outcomes are the numbers 1,2,3,4,5,6. So,
total number of possible outcomes =6 

The event is getting a number greater than 2 and numbers greater than 2 are 3,4,5,6. So, the number of favourable outcomes to the event getting a number greater than 2 =4 

Therefore , P(getting a number greater than 2) = `"Favourable outcomes"/"Total number of outcomes"` = `4/6` = `2/3`