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Question
An old woman decided to divide her gold among her daughter and daughters-in-law. She first kept exactly half of the gold for her daughter. Then she divided the rest of her gold among her daughters-in-law. The eldest one got 26 grams more than the youngest daughter-in-law. The middle one got twice as the youngest one. If the eldest daughter-in -law got 66 grams of gold, how much was received by the daughter?
Options
172 grams
186 grams
194 grams
192 grams
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Solution
186 grams
Explanation:
Eldest daughter-in-law = 66 gm of gold
Youngest daughter-in-law has = 40 gm of gold
Middle daughter-in-law has = 80 gm of gold
Altogether they have = 66 + 40 + 80 gm of gold
= 186 gm of gold
Therefore, daughter has = 186 gm of gold
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