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Question
An electric appliance has a rating of 1000 W–200 V. The resistance of the element of the electric appliance is:
Options
200 Ω
400 Ω
40 Ω
4000 Ω
MCQ
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Solution
40 Ω
Explanation:
$$R = \frac{V^2}{P}$$
$$= \frac{(200)^2}{1000}$$
= 40 Ω
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