Question

An electric appliance has a rating of 1000 W–200 V. The resistance of the element of the electric appliance is:

पर्याय

• 200 Ω

• 400 Ω

• 40 Ω

• 4000 Ω

Answer 1

40 Ω

Explanation:

$$R = \frac{V^2}{P}$$

$$= \frac{(200)^2}{1000}$$

= 40 Ω