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Question
An army contingent of 612 members is to march behind an army band of 48 members in a parade. The two groups are to march in the same number of columns. What is the maximum number of columns in which they can march?
Sum
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Solution
Let the number of columns be x.
Then, x is the largest number, which should divide both 612 and 48.
612 = 48 × 12 + 36
48 = 36 × 1 + 12
36 = 12 × 3 + 0
Since, HCF of 612 and 48 is x = 12.
Thus, 12 columns are required.
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