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Question
After the lagging and leading wattless currents cancel, what is the effective power?
Options
\[P=(I_q+I_q')V\]
\[P=I_qV\]
\[P=I_pV\]
\[P=I_q'V\]
MCQ
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Solution
Cancellation removes the wattless components from the effective current. The in-phase power component \[I_p\] remains, so power is effectively \[I_pV\].
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