Question

After the lagging and leading wattless currents cancel, what is the effective power?

पर्याय

• \[P=(I_q+I_q')V\]

• \[P=I_qV\]

• \[P=I_pV\]

• \[P=I_q'V\]

Answer 1

Cancellation removes the wattless components from the effective current. The in-phase power component \[I_p\] remains, so power is effectively \[I_pV\].