Advertisements
Advertisements
Question
Account for the following:
Aniline cannot be prepared by the ammonolysis of chlorobenzene under normal conditions.
Advertisements
Solution
In case of chlorobenzene, the C – Cl bond is quite difficult to break as it acquires a partial double bond character due to conjugation. So Under the normal conditions, ammonolysis of chlorobenzene does not yield aniline.
APPEARS IN
RELATED QUESTIONS
An aromatic compound 'A' of molecular formula C7H7ON undergoes a series of reactions as shown below. Write the structures of A, B, C, D and E in the following reactions :
Give the structures of A, B and C in the following reactions :
Why cannot aromatic primary amines be prepared by Gabriel phthalimide synthesis?
Answer the following
Write a reaction to convert acetic acid into methylamine.
Identify compound 'B' in following series of reactions?
\[\ce{Acetonitrile ->[Na/alcohol] A ->[NaNO2/dil.HCI] B}\]
In order to prepare a 1° amine from an alkyl halide with simultaneous addition of one \[\ce{CH2}\] group in the carbon chain, the reagent used as source of nitrogen is ______.
What is the product when \[\ce{C6H5CH2NH2}\] reacts with \[\ce{HNO2}\]?
Match the reactions given in Column I with the statements given in Column II.
| Column I | Column II | ||
| (i) | Ammonolysis | (a) | Amine with lesser number of carbon atoms |
| (ii) | Gabriel phthalimide synthesis | (b) | Detection test for primary amines. |
| (iii) | Hoffmann Bromamide reaction | (c) | Reaction of phthalimide with \[\ce{KOH}\] and \[\ce{R-X}\] |
| (iv) | Carbylamine reaction | (d) | Reaction of alkylhalides with \[\ce{NH3}\] |
Describe Gabriel's phthalimide synthesis. (Give reaction)
In the given reaction what is the X?
\[\begin{array}{cc}
\ce{O}\phantom{.......................}\\
||\phantom{.......................}\\
\phantom{}\ce{R - C - OH <-[H3O] Χ ->[H] RCH2NH2}
\end{array}\]
