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Abcd is a Trapezium with Ab Parallel to Dc. a Line Parallel to Ac Intersects Ab at X and Bc at Y. Prove that Area of ∆Adx = Area of ∆Acy.

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Question

ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersects AB at X and BC at Y.
Prove that the area of ∆ADX = area of ∆ACY.

Sum
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Solution

Join CX, DX and AY.
Now, triangles ADX and ACX are on the same base AX and between the parallels AB and DC.
∴ A( ΔADX ) = A( ΔACX )                            ….(i)

Also, triangles ACX and ACY are on the same base AC and between the parallels AC and XY.
∴ A( ΔACX ) = A( ΔACY )                            ….(ii)

From (i) and (ii), we get
A( ΔADX ) = A( ΔACY )



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Figures Between the Same Parallels
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Chapter 16: Area Theorems [Proof and Use] - Exercise 16 (C) [Page 202]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 16 Area Theorems [Proof and Use]
Exercise 16 (C) | Q 11 | Page 202

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