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Question
ABCD is a rhombus whose diagonals intersect at E. Then `vec(EA) + vec(EB) + vec(EC) + vec(ED)` equals
Options
`vec(0)`
`vec(AD)`
`2vec(BC)`
`2vec(AD)`
MCQ
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Solution
`bbvec(0)`
Explanation:
`vec(EA) + vec(EB) + vec(EC) + vec(ED)`
= `vec(EA) + vec(EB) - vec(EA) - vec(EB)`
= `vec(0)`
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