Question

ABCD is a rhombus whose diagonals intersect at E. Then `vec(EA) + vec(EB) + vec(EC) + vec(ED)` equals

पर्याय

• `vec(0)`

• `vec(AD)`

• `2vec(BC)`

• `2vec(AD)`

Answer 1

`bbvec(0)`

Explanation:

`vec(EA) + vec(EB) + vec(EC) + vec(ED)`

= `vec(EA) + vec(EB) - vec(EA) - vec(EB)`

= `vec(0)`