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Question
ΔABC ~ ΔPQR. In ΔABC, AB = 3.6 cm, BC = 4 cm, AC = 4.2 cm. The corresponding sides of ΔABC and ΔPQR are in the ratio 2 : 3. Construct ΔABC and ΔPQR.
Geometric Constructions
Sum
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Solution
In ΔABC, AB = 3.6 cm, BC = 4 cm, AC = 4.2 cm
ΔABC ~ ΔPQR
∴ `(AB)/(PQ) = (BC)/(QR) = (AC)/(PR) = 2/3`
`3.6/(PQ) = 4/(QR) = 4.2/(PR) = 2/3`
⇒ `3.6/(PQ) = 2/3`
PQ = `(3.6 xx 3)/2`
PQ = 1.8 × 3
PQ = 5.4 cm
⇒ `4/(QR) = 2/3`
QR = `(4 xx 3)/2`
QR = 2 × 3
QR = 6 cm
⇒ `4.2/(PR) = 2/3`
PR = `(4.2 xx 3)/2`
PR = 2.1 × 3
PR = 6.3 cm
Construction of triangles:
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