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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

ΔABC ~ ΔPQR. In ΔABC, AB = 3.6 cm, BC = 4 cm, AC = 4.2 cm. The corresponding sides of ΔABC and ΔPQR are in the ratio 2 : 3. Construct ΔABC and ΔPQR. - Geometry Mathematics 2

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प्रश्न

ΔABC ~ ΔPQR. In ΔABC, AB = 3.6 cm, BC = 4 cm, AC = 4.2 cm. The corresponding sides of ΔABC and ΔPQR are in the ratio 2 : 3. Construct ΔABC and ΔPQR.

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उत्तर

In ΔABC, AB = 3.6 cm, BC = 4 cm, AC = 4.2 cm

ΔABC ~ ΔPQR

∴ `(AB)/(PQ) = (BC)/(QR) = (AC)/(PR) = 2/3`

`3.6/(PQ) = 4/(QR) = 4.2/(PR) = 2/3`

⇒ `3.6/(PQ) = 2/3`

PQ = `(3.6 xx 3)/2`

PQ = 1.8 × 3

PQ = 5.4 cm

⇒ `4/(QR) = 2/3` 

QR = `(4 xx 3)/2`

QR = 2 × 3

QR = 6 cm

⇒ `4.2/(PR) = 2/3`

PR = `(4.2 xx 3)/2`

PR = 2.1 × 3

PR = 6.3 cm

Construction of triangles:

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