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A wire in the form of a circle of radius 42cm. It is bent into a square. Determine the side of the square and compare the area of the regions enclosed in the two cases.

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Question

A wire in the form of a circle of radius 42cm. It is bent into a square. Determine the side of the square and compare the area of the regions enclosed in the two cases.

Sum
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Solution

Let the side of the square = s and the radius of the circle = r
The Circumference of a circle with radius r = 2πr
The Circumference of a Circle with radius 42
= 2π x 42
= 264cm
The Area of a Circle with radius r
= πr2
= π(42)2
= 5544cm2
The Circumference of the Circle
= Perimeter of the square
⇒ Perimeter of the Square = 264cm
⇒ 4s = 264cm
⇒ s = 66cm
Area of a Square with side s = 4s2
Area of a Square with side 66
= 4(66)2
= 4356cm2
Ratio of Area of the Circle to the Area of the Square
= 5544:4356
= 14:11.

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Chapter 19: Perimeter and Area - Exercise 24.3

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Frank Mathematics Part 1 [English] Class 9 ICSE
Chapter 19 Perimeter and Area
Exercise 24.3 | Q 26

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