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Question
A two digit number is seven times the sum of its digits and also equal to 12 less than three times the product of its digits. Find the numbers.
Sum
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Solution
Let the tens digit be x and the units digit be y.
Form the number
Number = 10x + y
(i) Number is seven times the sum of its digits
10x + y = 7(x + y)
10x + y = 7x + 7y
3x = 6y
x = 2y ...(1)
(ii) Number is 12 less than three times the product of its digits
10x + y = 3(xy) − 12 ...(2)
Substitute x = 2y in equation (2)
10(2y) + y = 3(2y ⋅ y) − 12
21y = 6y2 − 12
6y2 − 21y − 12 = 0
Divide by 3:
2y2 − 7y − 4 = 0
(2y + 1) (y − 4) = 0
y = 4 or y = `-1/2`
x = 2y = 8
The required two-digit number is: 84
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