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Question
A rectangular field is 16 m long and 10 m wide. There is a path of uniform width all around it, having an area of 120 m2. Find the width of the path.
Sum
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Solution
Let the uniform width of the path be x m.
Original length = 16 m
Original width = 10 m
New length = 16 + 2x
New width = 10 + 2x
Area of path = Area of outer rectangle – Area of field
Given area of path = 120 m2
(16 + 2x) (10 + 2x) – (16 × 10) = 120
(16 + 2x) (10 + 2x) = 160 + 120 = 280
160 + 32x + 20x + 4x2 = 280
4x2 + 52x + 160 = 280
4x2 + 52x – 120 = 0
x2 + 13x – 30 = 0
(x + 15) (x – 2) = 0
The width of the path is 2 m.
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