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A Toy is in the Form of a Cylinder with Hemispherical Ends. If the Whole Length of the Toy is 90 Cm and Its Diameter is 42 Cm, Then Find the Cost of Painting the Toy at the Rate of 70 Paise per Sq Cm.

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Question

A toy is in the form of a cylinder with hemispherical ends. If the whole length of the toy is 90 cm and its diameter is 42 cm, then find the cost of painting the toy at the rate of 70 paise per sq cm.

Sum
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Solution

We have,

the total height of the toy = 90 cm and

the radius of the toy, r= 42/2 = 21 cm

Also,the height of the toy, r=`42/2 = 21 "cm"` 

Now , the total surface area of the toy =CSA of cylinder + 2 × CSA of a hemispher

`= 2pirh + 2 xx 2pir^2`

`= 2pir(h + 2r)`

`= 2xx22/7xx21xx(48+2xx21)`

`= 44xx3xx(48+42)`

`=44xx3xx90`

= 11880 cm2  

So, the cost of painting the toy =`(11880xx70)/100 =Rs  83,16`

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Chapter 17: Volumes and Surface Areas of Solids - Exercise 19A [Page 876]

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10
Chapter 17 Volumes and Surface Areas of Solids
Exercise 19A | Q 18 | Page 876

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