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A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is

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Question

A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is ______.

Options

  • 1 : 2

  • 2 : 1

  • 1 : 4

  • 4 : 1

MCQ
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Solution

A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is 2 : 1.

Explanation:

Let the radius of the hemisphere or the cone be r and the slant height of the cone be `l`.

Now, 

Surface area of the hemisphere = Surface area of the cone 

⇒ 2πr= πr`l`

`=> (pir^2)/(pirl) = 1/2`

`=> "r"/l = 1/2`

∴ r : `l` = 1 : 2

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Chapter 17: Volumes and Surface Areas of Solids - MULTIPLE-CHOICE QUESTIONS (MCQ) [Page 832]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 17 Volumes and Surface Areas of Solids
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 23. | Page 832
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