हिंदी

A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is

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प्रश्न

A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is ______.

विकल्प

  • 1 : 2

  • 2 : 1

  • 1 : 4

  • 4 : 1

MCQ
रिक्त स्थान भरें
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उत्तर

A solid is hemispherical at the bottom and conical (of same radius) above it. If the surface areas of the two parts are equal then the ratio of its radius and the slant height of the conical part is 2 : 1.

Explanation:

Let the radius of the hemisphere or the cone be r and the slant height of the cone be `l`.

Now, 

Surface area of the hemisphere = Surface area of the cone 

⇒ 2πr= πr`l`

`=> (pir^2)/(pirl) = 1/2`

`=> "r"/l = 1/2`

∴ r : `l` = 1 : 2

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अध्याय 17: Volumes and Surface Areas of Solids - MULTIPLE-CHOICE QUESTIONS (MCQ) [पृष्ठ ८३२]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 17 Volumes and Surface Areas of Solids
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 23. | पृष्ठ ८३२
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