Advertisements
Advertisements
Question
A solid has forty faces and sixty edges. Find the number of vertices of the solid.
Advertisements
Solution
By using Euler’s formula for polyhedron
F + V – E = 2
Given, Faces (F) = 40, Edges (E) = 60
⇒ 40 + V – 60 = 2
⇒ V – 20 = 2
⇒ V = 2 + 20 = 22
Hence, the vertices of the solid are 22.
APPEARS IN
RELATED QUESTIONS
In a solid if F = V = 5, then the number of edges in this shape is ______.
Which of the following cannot be true for a polyhedron?
If the sum of number of vertices and faces in a polyhedron is 14, then the number of edges in that shape is ______.
Look at the shapes given below and state which of these are polyhedra using Euler’s formula.

Look at the shapes given below and state which of these are polyhedra using Euler’s formula.

Look at the shapes given below and state which of these are polyhedra using Euler’s formula.

Using Euler’s formula, find the value of unknown y in the following table.
| Faces | y |
| Vertices | 12 |
| Edges | 18 |
Using Euler’s formula, find the value of unknown z in the following table.
| Faces | 9 |
| Vertices | z |
| Edges | 16 |
Can a polyhedron have V = F = 9 and E = 16? If yes, draw its figure.
Check whether a polyhedron can have V = 12, E = 6 and F = 8.
