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Question
In a solid if F = V = 5, then the number of edges in this shape is ______.
Options
6
4
8
2
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Solution
In a solid if F = V = 5, then the number of edges in this shape is 8.
Explanation:
Euler’s formula for any polyhedron is F + V – R = 2
Given, F = V = 5
On putting the values of F and V in the Euler’s formula, we get
5 + 5 – E = 2
⇒ 10 – E = 2
⇒ E = 8
Notes
F = Faces, V = Verticles and E = Edges
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| S.No | Solid | Shape of Solid |
Number of faces F |
Number of Verticles V |
Number of edges E |
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| a. | Cuboid | ![]() |
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| b. | Triangular Pyramid |
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| c. | Square Pyramid |
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| d. | Rectangular Pyramid |
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| e. | Pentagonal Pyramid |
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| f. | Hexagonal Pyramid |
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| g. | Triangular Prism |
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| h. | Square Prism |
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| i. | Cube | ![]() |
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| j. | Pentagonal Prism |
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| k. | Octagonal Prism |
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| l. | Heptagonal Prism |
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| Vertices | 11 |
| Edges | r |
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