A small manufacturer has employed 5 skilled men and 10 semiskilled men and makes an article in two qualities deluxe model and an ordinary model. The making of a deluxe model requires 2 hrs. work by a skilled man and 2 hrs. work by a semiskilled man. The ordinary model requires 1 hr by a skilled man and 3 hrs. by a semiskilled man. By union rules no man may work more than 8 hrs per day. The manufacturers clear profit on deluxe model is Rs 15 and on an ordinary model is Rs 10. How many of each type should be made in order to maximize his total daily profit.
Solution
Let x articles of deluxe model and y articles of an ordinary model be made.
Number of articles cannot be negative.
Therefore, \[x, y \geq 0\]
According to the question, the making of a deluxe model requires 2 hrs. work by a skilled man and the ordinary model requires 1 hr by a skilled man
The making of a deluxe model requires 2 hrs. work by a semiskilled man ordinary model requires 3 hrs. work by a semiskilled man.
Thus, the mathematical formulation of the given linear programmimg problem is
Max Z = \[15x + 10y\]
\[2x + 3y \leq 80\]
\[y \geq 0\]
The corner points are A(0, \[\frac{80}{3}\]B(10, 20), C(20, 0)
The values of Z at these corner points are as follows
Corner point  Z= 15x+10y 
A 
\[\frac{800}{3}\]

B  350 
C  300 
The maximum value of Z is 300 which is attained at C(20, 0)
Thus, the maximum profit is Rs 300 obtained when 10 units of deluxe model and 20 unit of ordinary model is produced