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A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (see figure).

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Question

A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground (see figure). If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.

Diagram
Sum
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Solution


Given, dimensions of playground = 120 m × 80 m

∵ Area of rectangle ABCD = 120 × 80 = 9600 m2

Area of rectangle ABFE = AB × BF

= 120 × 3  ...[∵ Area of rectangle = Length × Breadth]

= 360 m2  

Area of rectangle GHIJ = JI × IH

= 2 × 77

= 154 m2

∴ Area of remaining ground rectangle GHIJ = Area of rectangle ABCD – Area of rectangle ABFE – Area of GHIJ

= 9600 – 360 – 154

= 9086 m2

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Chapter 9: Perimeter and Area - Exercise [Page 293]

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NCERT Exemplar Mathematics Exemplar Class 7
Chapter 9 Perimeter and Area
Exercise | Q 115. | Page 293

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