Advertisements
Advertisements
Question
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
Advertisements
Solution
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
number of homozygous dominant fruit flies is As,
p2(AA) = (0.6)2
= 0.36
= 0.36 × 200
= 72
APPEARS IN
RELATED QUESTIONS
Multiple choice question.
In Hardy - Weinberg equation, the frequency of homozygous recessive individual is represented by:
Very short answer question.
State the Hardy – Weinberg equilibrium.
Explain how mutations, natural selection and genetic drift affect Hardy Weinberg equilibrium.
In a population, Hardy Weinberg equilibrium is disturbed by following factors EXCEPT ______.
In the Hardy-Weinberg equilibrium equation, the homozygous mutant is represented as ______.
In a certain population, the frequency of three genotypes is as follows:
| Genotypes: | BB | Bb | bb |
| frequency: | 22% | 62% | 16% |
What is the likely frequency of B and b alleles?
Gene flow occurs through generations. and can occur across language barriers in humans. If we have a technique of measuring specific allele frequencies in different population of the world, can we not predict human migratory patterns in pre-history and history? Do you agree or disagree? Provide explanation to your answer.
Enumerate three most characteristic criteria for designating a Mendelian population.
Give a mathematical expression for Hardy Weinberg's principle.
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of carrier fruit flies.
