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प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
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उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
number of homozygous dominant fruit flies is As,
p2(AA) = (0.6)2
= 0.36
= 0.36 × 200
= 72
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संबंधित प्रश्न
What does the following equation represent? Explain:
p2 + 2pq + q2 = 1.
Differentiate between Directional natural selection and Disruptive natural selection.
How does the Hardy-Wienberg equation explain genetic equilibrium?
Very short answer question.
State the Hardy – Weinberg equilibrium.
(p + q)2 = p2 + 2pq + q2 = 1 represents an equation used in ______.
Hardy Weinberg's principle explains ______
“Migration may enhance or blurr the effects of selection”. Comment.
Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values?
List any two factors that can disturb the genetic equilibrium.
The graphs below show three types of natural selection. The shaded areas marked with arrows show the individuals in the population who are not selected. The dotted vertical lines show the statistical means.
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| character Graph A |
character Graph B |
character Graph C |
- What names are given to the types of selection shown in graphs A, B and C?
- After the selection has operated for several generations in the above populations indicated as, Graph A, B and C, graphically illustrate the probable results.



