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प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
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उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
number of homozygous dominant fruit flies is As,
p2(AA) = (0.6)2
= 0.36
= 0.36 × 200
= 72
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संबंधित प्रश्न
What does the following equation represent? Explain:
p2 + 2pq + q2 = 1.
State Hardy-Weinberg’s principle.
What is the Founder's effect?
How does the Hardy-Wienberg equation explain genetic equilibrium?
In a population, Hardy Weinberg equilibrium is disturbed by following factors EXCEPT ______.
“Migration may enhance or blurr the effects of selection”. Comment.
The graphs below show three types of natural selection. The shaded areas marked with arrows show the individuals in the population who are not selected. The dotted vertical lines show the statistical means.
 |
 |
 |
| character Graph A |
character Graph B |
character Graph C |
- What names are given to the types of selection shown in graphs A, B and C?
- After the selection has operated for several generations in the above populations indicated as, Graph A, B and C, graphically illustrate the probable results.
Write Hardy Weinberg's equation.
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of carrier fruit flies.
Which one of the following factors will not affect the Hardy-Weinberg equilibrium?
