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प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
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उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
number of homozygous dominant fruit flies is As,
p2(AA) = (0.6)2
= 0.36
= 0.36 × 200
= 72
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संबंधित प्रश्न
p2 + 2pq + q2 = 1. Explain this algebraic equation on the basis of Hardy Weinberg's principle.
With the help of an algebraic equation, how did Hardy-Weinberg explain that in a given population the frequency of occurrence of alleles of a gene is supposed to remain the same through generations?
Differentiate between Directional natural selection and Disruptive natural selection.
Enumerate three most characteristic criteria for designating a Mendelian population.
State Hardy Weinberg's principle.
Give a mathematical expression for Hardy Weinberg's principle.
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous recessive fruit flies.
Which one of the following factors will not affect the Hardy-Weinberg equilibrium?
What is the primary statement of Hardy-Weinberg's principle?
What biological significance does the heterozygous genotype hold in populations at Hardy-Weinberg equilibrium?
