Advertisements
Advertisements
प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous recessive fruit flies.
Advertisements
उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
p = 1 − 0.4
p = 0.6
number of homozygous recessive fruit flies is
As, q2(aa) = (0.4)2
= 0.16
= 0.16 × 200
= 32
APPEARS IN
संबंधित प्रश्न
What does the following equation represent? Explain:
p2 + 2pq + q2 = 1.
State Hardy-Weinberg’s principle.
How does Hardy-Weinberg’s expression (p2+2pq+q2=1) explain that genetic equilibrium is maintained in a population? List any four factors that can disturb the genetic equilibrium.
For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be ______.
In a certain population, the frequency of three genotypes is as follows:
| Genotypes: | BB | Bb | bb |
| frequency: | 22% | 62% | 16% |
What is the likely frequency of B and b alleles?
How is Hardy-Weinberg's expression “(p2 + 2pq + q2) = 1” derived?
At a particular locus, the frequency of allele A is 0.8, and that of allele a is 0.2. What would be the frequency of heterozygotes in a random mating population at equilibrium?
The graphs below show three types of natural selection. The shaded areas marked with arrows show the individuals in the population who are not selected. The dotted vertical lines show the statistical means.
 |
 |
 |
| character Graph A |
character Graph B |
character Graph C |
- What names are given to the types of selection shown in graphs A, B and C?
- After the selection has operated for several generations in the above populations indicated as, Graph A, B and C, graphically illustrate the probable results.
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
Frequency of the allele (A).
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of carrier fruit flies.
