Advertisements
Advertisements
प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of carrier fruit flies.
Advertisements
उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
Number of carrier fruit flies is
As, 2pq (Aa)
= 2 × 0.6 × 0.4
= 0.48
= 0.48 × 200
= 96
APPEARS IN
संबंधित प्रश्न
What does the following equation represent? Explain:
p2 + 2pq + q2 = 1.
Differentiate between Directional natural selection and Disruptive natural selection.
How does the Hardy-Wienberg equation explain genetic equilibrium?
A population will not exist in Hardly Weiberg equilibrium if ____________.
In the Hardy-Weinberg equilibrium equation, the homozygous mutant is represented as ______.
For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be ______.
Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values?
List any two factors that can disturb the genetic equilibrium.
Write Hardy Weinberg's equation.
Which one of the following factors will not affect the Hardy-Weinberg equilibrium?
