Advertisements
Advertisements
प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of carrier fruit flies.
Advertisements
उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
Number of carrier fruit flies is
As, 2pq (Aa)
= 2 × 0.6 × 0.4
= 0.48
= 0.48 × 200
= 96
APPEARS IN
संबंधित प्रश्न
Give the graphical representation of Hardy· Weinberg's principle in the form of Punnet Square.
p2 + 2pq + q2 = 1. Explain this algebraic equation on the basis of Hardy Weinberg's principle.
What is the Founder's effect?
Very short answer question.
State the Hardy – Weinberg equilibrium.
Explain how mutations, natural selection and genetic drift affect Hardy Weinberg equilibrium.
(p + q)2 = p2 + 2pq + q2 = 1 represents an equation used in ______.
Hardy - Weinberg equilibrium is known to be affected by gene - flow, genetic drift, mutation, genetic recombination and
Which type of selection explains industrial melanism observed in moth, Biston bitularia?
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous recessive fruit flies.
