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प्रश्न
How is Hardy-Weinberg’s expression “(p2 + 2pq + q2) = 1” derived?
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उत्तर
Sum total of all the allelic frequencies is 1. Let there be two alleles A and a in a population. The frequencies of alleles A and a are ‘p’ and ‘q’ respectively.
The frequency of AA individuals in a population is p2 and it can be explained that the probability that an allele A with a frequency of p would appear on both the chromosomes of a diploid individual is simply the product of the probabilities, i.e., p2.
Similarly, the frequency of aa is q2 and that of Aa is 2pq.
(p2 + 2pq + q2) = 1 where p2 represents the frequency of the homozygous dominant genotype, 2pq represents the frequency of the heterozygous genotype and q2 represents the frequency of the homozygous recessive.
संबंधित प्रश्न
p2 + 2pq + q2 = 1. Explain this algebraic equation on the basis of Hardy Weinberg's principle.
According to the Hardy-Weinberg principle, the allele frequency of a population remains constant. How do you interpret the change of frequency of alleles in a population?
Explain how mutations, natural selection and genetic drift affect Hardy Weinberg equilibrium.
Hardy Weinberg's principle explains ______
In a certain population, the frequency of three genotypes is as follows:
| Genotypes: | BB | Bb | bb |
| frequency: | 22% | 62% | 16% |
What is the likely frequency of B and b alleles?
State and explain any three factors affecting allele frequency in populations.
Enumerate three most characteristic criteria for designating a Mendelian population.
Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values?
Explain Hardy-Weinberg's principle
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
