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प्रश्न
How is Hardy-Weinberg’s expression “(p2 + 2pq + q2) = 1” derived?
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उत्तर
Sum total of all the allelic frequencies is 1. Let there be two alleles A and a in a population. The frequencies of alleles A and a are ‘p’ and ‘q’ respectively.
The frequency of AA individuals in a population is p2 and it can be explained that the probability that an allele A with a frequency of p would appear on both the chromosomes of a diploid individual is simply the product of the probabilities, i.e., p2.
Similarly, the frequency of aa is q2 and that of Aa is 2pq.
(p2 + 2pq + q2) = 1 where p2 represents the frequency of the homozygous dominant genotype, 2pq represents the frequency of the heterozygous genotype and q2 represents the frequency of the homozygous recessive.
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संबंधित प्रश्न
State Hardy-Weinberg’s principle.
Differentiate between Directional natural selection and Disruptive natural selection.
A population will not exist in Hardly Weiberg equilibrium if ____________.
In the Hardy-Weinberg equilibrium equation, the homozygous mutant is represented as ______.
Hardy - Weinberg equilibrium is known to be affected by gene - flow, genetic drift, mutation, genetic recombination and
For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be ______.
Which type of selection explains industrial melanism observed in moth, Biston bitularia?
In a certain population, the frequency of three genotypes is as follows:
| Genotypes: | BB | Bb | bb |
| frequency: | 22% | 62% | 16% |
What is the likely frequency of B and b alleles?
State and explain any three factors affecting allele frequency in populations.
Write Hardy Weinberg's equation.
