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प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
Frequency of the allele (A).
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उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
Frequency of allele, p(A) = 1 − 0.4
= 0.6
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संबंधित प्रश्न
According to the Hardy-Weinberg principle, the allele frequency of a population remains constant. How do you interpret the change of frequency of alleles in a population?
Multiple choice question.
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Very short answer question.
State the Hardy – Weinberg equilibrium.
Explain how mutations, natural selection and genetic drift affect Hardy Weinberg equilibrium.
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Enumerate three most characteristic criteria for designating a Mendelian population.
Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values?
List any two factors that can disturb the genetic equilibrium.
At a particular locus, the frequency of allele A is 0.8, and that of allele a is 0.2. What would be the frequency of heterozygotes in a random mating population at equilibrium?
