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A particular element (A) has one electron in its third shell. There is another element (B) with six electrons in its second shell. (i) How many electrons does A tend to give or take to become stable?

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Question

A particular element (A) has one electron in its third shell. There is another element (B) with six electrons in its second shell.

  1. How many electrons does A tend to give or take to become stable?
  2. What kind of ion would it form? 
  3. How many electrons does B tend to give or take to become stable? 
  4. What kind of ion would it form? 
  5. If A and B were to combine, what kind of bond would be formed?
  6. What would be the formula for the compound thus formed?
Short Answer
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Solution

  • A is sodium (configuration 2,8,1): it tends to lose 1 electron, forming a cation, Na⁺.
  • B is oxygen (2,6): it tends to gain 2 electrons, forming an anion, O²⁻.
  • A and B combine by an ionic bond, giving the formula Na₂O.
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Chapter 9: Atomic Foundations of Matter - Revise, Reflect, Refine [Page 181]

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NCERT Science Exploration [English] Class 9
Chapter 9 Atomic Foundations of Matter
Revise, Reflect, Refine | Q 1. | Page 181
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