Question

A pair of dice is thrown. Find the probability that the sum of the numbers obtained is more than ten.

Answer 1

Given: A pair of fair six-sided dice is thrown once. Find P(sum > 10).

Step-wise calculation:

1. Total number of equally likely outcomes = 6 × 6 = 36.

2. Favourable outcomes (sum > 10) are (5, 6), (6, 5), (6, 6) → 3 outcomes.

3. Probability = `"Number of favourable outcomes"/"Total outcomes"`

= `3/36`

= `1/12`

= 0.0833

Required probability = `1/12`.