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प्रश्न
A pair of dice is thrown. Find the probability that the sum of the numbers obtained is more than ten.
बेरीज
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उत्तर
Given: A pair of fair six-sided dice is thrown once. Find P(sum > 10).
Step-wise calculation:
1. Total number of equally likely outcomes = 6 × 6 = 36.
2. Favourable outcomes (sum > 10) are (5, 6), (6, 5), (6, 6) → 3 outcomes.
3. Probability = `"Number of favourable outcomes"/"Total outcomes"`
= `3/36`
= `1/12`
= 0.0833
Required probability = `1/12`.
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